Test your knowledge with AI-generated multiple choice questions
HST adds $13\%$ of the price, which is equivalent to multiplying by $1.13$. The cost for $x$ notebooks is $2.49x$, so multiply by $1.13$ to include tax. Adding $1.13$ or subtracting $0.13$ is incorrect.
Distribute: $1.05\cdot4x=4.20x$, $1.05\cdot3=3.15$, and $-0.05(2x-1)=-0.10x+0.05$. Combine: $(4.20x-0.10x)+(3.15+0.05)=4.10x+3.20=4.1x+3.2$.
Perimeter is $2(L+W)$. So $2(3x+(x-2))=2(3x+x-2)$. Option A is area. Option C forgets to double. Option D subtracts $x$ incorrectly.
Add like terms: $2x^2+x^2=3x^2$, $-3x+x=-2x$, and $1-4=-3$. So $3x^2-2x-3$.
Compute $-2(3y-4)=-6y+8$ and $5(2-y)=10-5y$. Sum: $(-6y-5y)+(8+10)=-11y+18$.
Group like terms: $4a-2a=2a$, $3b-b=2b$, and $5-7=-2$. Thus $2a+2b-2$.
Distribute: $3(2x-5)=6x-15$ and $-4(x+1)=-4x-4$. Combine: $(6x-4x)+(-15-4)=2x-19$.
Add the pre-tax polynomials: $(5x+2)+(3x-1)=8x+1$. Multiply by $1.13$ for HST to get $1.13(8x+1)$.
The variable part is distance times the per-km rate: $1.80k$. Then add the fixed fee $4$. The other options mistakenly multiply the flat fee by $k$ or misplace multiplication and addition.
Distribute the subtraction: $3y^2-5y+2-y^2-y+6$. Combine like terms to get $2y^2-6y+8$.
Length is $w+3$. Perimeter is $2(l+w)=2((w+3)+w)=2(2w+3)$. Options $2w+3$ and $2w+6$ miss the doubling of both sides; $w^2+3$ is an area-like expression, not a perimeter.
Three notebooks cost $3\times2.50=7.50$, written as $3(2.50)$. Add $p$ for the pen, giving $3(2.50)+p$. Options C and D incorrectly multiply the pen cost; B omits two notebooks.
Combine the $x$ terms: $5x+2x-x=6x$. Combine constants: $-3+7=4$. So the result is $6x+4$.
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